PINE
OIL
DIETARY
ASSESSMENT
FROM:
A.
Najm
Shamim,
Ph.
D.,
Chemist
Regulatory
Management
Branch
II
Antimicrobials
Division
(
7510C)

To:
Michelle
Centra,
Science
Coordinator
for
Pine
Oils
RED
Regulatory
Management
Branch
II
Antimicrobials
Division
(
7510C)

Thru:
Ben
Chambliss,
Team
Leader
Regulatory
Management
Branch
II
Antimicrobials
Division
(
7510C)

And
Connie
Welch,
Chief
Regulatory
Management
Branch
II
Antimicrobials
Division
(
7510C)
Page
2
of
4
Residue
Information:

Review
of
the
Agency's
residue
chemistry
database
does
not
show
any
residues
related
to
pine
oil
on
any
RACs.
The
Agency
did
not
require
any
residue
chemistry
data
nor
any
were
submitted.
Therefore,
no
residue
chemistry
data
and
analyses
are
included
in
this
dietary
exposure
section
on
pine
oils.

Major
use
of
pine
oil
solution
formulations
is
as
disinfectant.
The
Agency
does
not
have
any
guideline
studies
on
sanitizer
and
disinfectant
use
of
pesticides.
Label
search
shows
that
currently
there
are
a
number
of
products
registered
with
the
Agency
in
which
the
active
is
the
Pine
Oil,
as
disinfectants,
and
the
use
pattern
of
these
formulations
result
in
the
indirect
food
contact
of
the
active.
The
product
are
listed
along
with
the
method
of
applications
in
Table
I.

Table
I
Product
formulation
%
Active
Indirect
Food
Contact/
Use
Pattern
Lonza
Formulation
P­
13
EPA
Reg#;
6838­
168
7.90%
Restaurants,
food
and
meat
processing
plants,
Method
of
Application:
Dilute
2
oz
of
P­
13
to
1
gallon
water
OR
1
part
of
the
product/
63
parts
of
water
Lonza
Formulation
P­
6
EPA
Reg#:
6838­
169
3.95%
Restaurants,
cafeterias,
kitchen,
food
storage
areas,
counter
tops,
stove
tops,
microwave
oven.
Method
of
Application:
Dilute
4
oz
of
P­
6/
gallon
water
or
1
part
active/
32
parts
of
water
Lonza
Formulation
P­
39
EPA
Reg#:
6838­
177
23.81%
Restaurant,
cafeterias,
kitchens,
food
storage
area,
counter
tops,
cabinets,
picnic
table,
microwave
oven
Method
of
Application:
1.3
oz
of
P­
39/
2
gallon
water
Or
1
part
active/
190
parts
water
or
1.25
oz
active/
gallon
water
Or
1
part
active/
100
parts
water
El­
Pinol­
60
EPA
REg#:
11668­
13
60%
Kitchen,
stoves,
drain
boards.
Method
of
Application:
4
table
spoon/
gallon
water
Or
50
parts
active/
50
parts
water
(
1:
1
dilution)
Page
3
of
4
Product
formulation
%
Active
Indirect
Food
Contact/
Use
Pattern
El­
Pinol­
19.9
%
EPA
Reg#:
11668­
17
19.9%
Kitchen
stoves,
drain
boards
Method
of
Application:
0.25
cup
active/
gallon
water
or
0.5
cup
of
active/
0.5
cup
water
(
1:
1
dilution)

To
estimate
the
Estimated
Daily
Intake
(
EDI),
the
Agency
has
used
the
following
formula:

EDI
=
(
Wash
solution,
mg/
cm2)
x
wt.
fraction
of
wash
solution
(
AR)
x
SA
x
FMF/
BW
­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­­
­­­­(
1)

Where:
AR
=
Application
rate
SA
=
surface
are
to
which
food
is
exposed,
assume
2000
cm2
FMF
=
Fraction
of
pesticide
migrating
to
food,
assume
10%*
BW
=
70
for
male
adults,
60
kg
for
female
adults
and
15
kg
for
children
1.
El­
Pinol­
60:
this
product
contains
60%
Pine
Oil
and
is
used
as
4
table
spoon/
gallon
of
water.
The
wt.
fraction
of
this
use
pattern
=
0.0157
Substitution
in
eq.
1:

(
mg/
cm2
)
0.0157
x
0.10
x
2000
cm2
/
BW
=
3.14
/
BW
3.14/
70
kg
=
0.0448
mg/
kg/
day
for
male
adult
3.14/
60kg
=
0.0.523
mg/
kg/
day
for
female
adult
3.14/
15
kg
=
0.20
mg/
kg/
day
for
children
2.
El­
Pinol­
19.9:
this
product
contains
19.9%
of
Pine
Oil
in
the
formulation
and
is
used
as
2
oz/
gallon
of
water
(
0.25
cup/
gallon
water).

Using
eq.
1:

(
mg/
cm2
)
x
0.199
x
0.
1
x
0.031
x
2000
cm2
/
BW
=
1.23
/
BW
Page
4
of
4
=
1.23/
70
kg
=
0.0175
mg/
kg/
day
for
a
male
adult
=
1.23
/
60
kg
=
0
.0205
mg/
kg/
day
for
a
female
adult
=
1.23
/
15
kg
=
0.082
mg/
kg/
day
for
a
child
3.
Lonza
P­
13:
7.9%
and
dilution
is
2
oz/
gallon
of
water.

Using
eq.
1:

(
mg/
cm2
)
x
0.079
x
0.031
x
0.10
x
2000
cm2
/
BW
=
0.4898/
BW
=
0.49/
70
kg
=
0.007
mg/
kg/
day
for
a
male
adult
=
0.49/
60kg
=
0.0081
mg/
kg/
day
for
a
female
adult
=
0.49/
15
kg
=
0.032
mg/
kg/
day
for
a
child
4.
Lonza
P­
6:
3.95
%
and
dilution
oz/
gallon
of
water
Using
eq.
1:

=(
mg/
cm2
)
x
0.0395
x
0.10
x
0.31
x
2000
cm2/
BW
=
0.246/
BW
=
0.246/
70
kg
=
0.0035
mg/
kg/
day
for
a
male
adult
=
0.246/
60
kg
=
0.0041
mg/
kg/
day
for
a
female
adult
=
0.246/
15
kg
=
0.0164
mg/
kg/
day
for
a
child
5.
Lonza
P­
39
and
the
dilution
is
0.65
oz/
gallon
=
0.005
Using
eq.
1:

=
(
mg/
cm2
)
x
0.005
x
0.10
x
0.238
x
2000
cm2
=
0.238/
BW
=
0.238/
70
kg
=
0.0034
mg/
kg/
day
for
a
male
adult
=
0.238/
60
kg
=
0.0039
mg/
kg/
day
for
a
female
adult
=
0.238/
15
kg
=
0.0158
mg/
kg/
day
for
a
child.

*
HED
has
used
a
similar
equation
in
which
exposure
to
hand
by
a
chemical
use
was
taken
as
10%.
